Permutation
represents a mathematical permutation. Permutation
can be inputted in both one-line and cycle notation using .p
property. Permutation
can can represent both permutational symmetry or antisymmetry.[].p
represents identity permutation.Permutation
in byte[]
, short[]
or int[]
array dynamically choosing the representation according to the degree of permutation.
Input Permutation
in one-line or cycle notation:
//permutation in one-line notation def p1 = [0, 2, 5, 6, 7, 1, 3, 4].p //same permutation in cycle notation def p2 = [[1, 2, 5], [4, 7], [3, 6]].p assert p1 == p2
Permutation
may represent permutational symmetry or antisymmetry; in order to convert symmetry to antisymmetry and vice versa one can use minus:
//antisymmetry def asym = -[[0, 4, 2], [1, 3]].p //symmetry def sym = -asym
One should be careful when inputting antisymmetries, since if a permutation order is odd (i.e. $p^r = 1$, where $p$ is a permutation and $r$ its order which is odd), then, obviously, such antisymmetry is inconsistent and Redberry will throw exception:
def perm = [[0, 2, 5], [6, 7, 4]].p println perm.order()
> 3
//this will throw exception println -perm
> InconsistentGeneratorsException
One can apply permutation to some list using right shift operator:
def p = [[0, 1], [2, 3]].p println p >> [10, 9, 8, 7]
> [9, 10, 7, 8]
println p >> ['a', 'b', 'c', 'd', 'e']
> [b, a, d, c, e]
The algebraic operations on permutations (composition, pow, inverse) can be performed in the following way:
def p = [[0, 5, 4], [1, 3]].p //inverse println p**(-1)
>[[0, 4, 5], [1, 3]]
//p1 * p1 * p1 println p**(3)
> [[1, 3]]
//inverse of (p1 * p1) println p**(-2)
> [[0, 5, 4]]
def oth = [[0, 1], [2, 3]].p //apply oth after p println p * oth
> [[0, 5, 4, 1, 2, 3]]
//apply p after oth println oth * p
> [[0, 3, 2, 1, 5, 4]]
The convention on composition of permutations is the following: if a
and b
two permutations, then the result of applying composition a*b
is equivalent to applying b
after a
.
In order to obtain a new position of i-th element under permutation one can use []
operator:
def p = [[0, 5, 4], [1, 3]].p assert p[0] == 5 assert p[4] == 0
The following table summarises some additional features of Permutation
:
.degree() |
returns degree of permutation, i.e. largest moved point plus one. |
.order() |
calculates and returns the order of permutation. |
.parity() |
returns parity of permutation (0 for even and 1 for odd). |
.antisymmetry() |
returns whether Permutation is antisymmetry. |
More specialised features of Permutation
can be found in API (see JavaDocs).